genomic constitution
1.Tbe present paper did not agree with the opinions. According tothe karyotype comparison (Table 1)or morphological characters, the authorrecognized that the genomic constitution of S. sempervirens must have beenAAAABB but not A_1A_1A_1A_1A_2A_2. The species of Cunninghamia could not bethe parients of Sequoia and they might be “Metasequoia” and “Sequoiadendron”.
